How many pounds of BOD are removed daily at a sewage treatment plant with an average BOD removal of 200 ppm for a flow of 1.5 MGD?

To calculate the amount of Biochemical Oxygen Demand (BOD) removed daily at a sewage treatment plant, the formula used is:

[

\text{Daily BOD Removal (lbs/day)} = \text{Flow (MGD)} \times \text{BOD Concentration (ppm)} \times \text{Conversion Factor}

]

In this case, flow is given as 1.5 million gallons per day (MGD), and the BOD concentration is 200 parts per million (ppm). The conversion factor to convert from ppm to pounds is approximately 8.34 (as there are 8.34 pounds in a million gallons of water).

Calculating the daily BOD removal involves the following steps:

1. Convert the flow from million gallons to gallons:

• 1.5 MGD = 1.5 million gallons = 1,500,000 gallons.

2. Apply the formula:

• BOD removal (lbs/day) = 1,500,000 gallons/day * 200 ppm * 8.34 lbs/million gallons.

This simplifies to:

• BOD removal = 1,500,000 * 200 * 8.34 / 1,000,